(c^2+8c-20)/(c-2)=0

Solution for (c^2+8c-20)/(c-2)=0 equation:

(c^2+8c-20)/(c-2)=0


Domain of the equation: (c-2)!=0

We move all terms containing c to the left, all other terms to the right

c!=2

c∈R


We multiply all the terms by the denominator


(c^2+8c-20)=0

We get rid of parentheses

c^2+8c-20=0

a = 1; b = 8; c = -20;
Δ = b2-4ac
Δ = 82-4·1·(-20)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12}{2*1}=\frac{-20}{2}
=-10
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12}{2*1}=\frac{4}{2}
=2
$